Bearings
A bearing is a clockwise angle measured from due North, written as a three-digit number from 000° to 360°, used to specify direction in navigation and surveying. Key result: any direction is uniquely encoded as a single angle in [000°, 360°), and the bearing of B from A differs from the bearing of A from B by exactly 180°. Applies to: navigation, surveying, orienteering, aviation, and trigonometric problem-solving. Origin: centuries of maritime and military practice, formalised with the magnetic compass.
Direction can be reduced to a single number. By fixing one reference direction (North) and one sense of rotation (clockwise), every possible heading becomes a unique angle between 000° and 360°. This converts the geometric idea of "which way" into arithmetic and trigonometry, letting us calculate distances, return paths, and positions.
Formal Statement
A three-figure bearing is the angle θ, measured clockwise from the North direction to the line of travel, expressed using three digits:
Derivation hint: A full rotation is 360°; North maps to both 000° and 360°, so we adopt 000° and exclude 360° to make each direction unique. Symbols:
- θ — the bearing (degrees)
- 000° — due North
- 090° — due East
- 180° — due South
- 270° — due West
Always write three digits: a bearing of 5° is written 005°, and 40° is written 040°.
A compass bearing describes direction relative to North or South, then rotated toward East or West, e.g. N30°E (start facing North, rotate 30° toward East) or S70°W. Each compass bearing corresponds to exactly one three-figure bearing.
If the bearing of point B from point A is θ, then the bearing of A from B (the back bearing) is:
Derivation hint: A and B lie on the same straight line; the two viewing directions are exactly opposite, differing by a half-turn (180°), with ±180° chosen to keep the result in [000°, 360°).
Why It Holds / Derivation
We show the return direction is a half-turn from the outgoing direction. 1. Set up two parallel Norths. At A and at B, North points the same way, because on the scale of map problems we treat North lines as parallel. 2. Identify the transversal. The straight line AB cuts both North lines. The bearing of B from A is the clockwise angle at A from North to AB; the bearing of A from B is the clockwise angle at B from North to BA. 3. Use co-interior (allied) angles. The two North lines are parallel and AB is a transversal. Working with the angles the line makes, the outgoing direction (North to B) and the return direction (North to A) point in opposite senses along the same line. 4. Opposite directions differ by 180°. Since BA is the reverse of AB, the return bearing is the outgoing bearing rotated by half a full turn: θ ± 180°. 5. Keep it in range. To remain inside [000°, 360°), add 180° when θ < 180°, and subtract 180° otherwise. ∎
∎Imagine standing at A looking toward B. Now imagine walking to B and turning around to look back at A — you have spun halfway round, a 180° about-face. Whatever your heading was, it is now reversed. That is the entire content of the back-bearing rule: a U-turn is exactly half a circle.
Building Intuition
Think of the compass rose as a clock face that has been renumbered. On a clock, 12 is at the top; on a compass, North is at the top (000°). But instead of 12 hours we use 360°, and we still go clockwise: 3 o'clock is East (090°), 6 o'clock is South (180°), 9 o'clock is West (270°). Any in-between heading is just the clockwise angle from the top. Because we always measure the same way (clockwise) from the same start (North), nobody can confuse "30 degrees" — it can only mean one direction.
Worked Examples
Given: The bearing of a lighthouse L from a boat B is 072°. Find the bearing of the boat from the lighthouse.
Steps: 1. The outgoing bearing is θ = 072°, which is less than 180°. 2. Apply Equation [2]: θ_back = θ + 180°. 3. θ_back = 072° + 180° = 252°.
Answer:
Given: A ship sails 8 km from port P on a bearing of 040° to point Q, then turns and sails 5 km on a bearing of 160° to point R. Find the straight-line distance PR.
Steps: 1. At Q, find the interior angle ∠PQR. The bearing back to P (back bearing of 040°) is 040° + 180° = 220°. The next leg leaves Q on 160°. 2. The angle between direction QP (220°) and direction QR (160°) is 220° − 160° = 60°. So ∠PQR = 60°. 3. Apply the cosine rule with PQ = 8, QR = 5:
Derivation hint: This is the Law of Cosines applied to triangle PQR, treating the bearing-difference at Q as the included angle. 4. PR² = 8² + 5² − 2(8)(5)cos60° = 64 + 25 − 80(0.5) = 89 − 40 = 49. 5. PR = √49 = 7.
Answer:
Common Misconceptions
Bearings are NOT measured the way mathematical angles are. In standard trigonometry, angles are measured anticlockwise from the positive x-axis (East). Bearings are measured clockwise from North. To convert a bearing θ into a standard angle α for plotting on x–y axes, use:
Derivation hint: Swapping the reference from North (up) to East (right) shifts by 90°, and reversing clockwise to anticlockwise flips the sign of θ. Forgetting this gives points reflected or rotated wrongly. Always check whether a problem wants a bearing or a standard angle.
Always use three digits. Writing "5°" for a bearing is wrong on an exam; it must be 005°. The three-figure convention exists precisely to prevent misreading and to standardise communication.
Claim (false): "The back bearing is always the outgoing bearing minus 180°."
Counterexample: Take an outgoing bearing of 030°. Subtracting gives 030° − 180° = −150°, which is not a valid bearing — it lies outside [000°, 360°). The correct back bearing is 030° + 180° = 210°. The rule requires adding 180° when θ < 180° and subtracting when θ ≥ 180°, exactly so the result stays in range.
Connections
Bearings sit at the meeting point of geometry and trigonometry. Solving bearing problems almost always reduces to Trigonometry — using the Sine Rule and Cosine Rule inside triangles whose angles come from bearing differences. The clockwise-from-North convention is a special case of Angle Measurement, related to the Unit Circle but rotated and reflected. Plotting bearings on a grid links to Coordinate Geometry and to Vectors, since a "distance on a bearing" is exactly a displacement vector. The parallel-North reasoning behind back bearings relies on Parallel Lines and Transversals and their angle properties.
Real-World Applications
Historical Development
Subtleties & Limits
The simple three-figure bearing assumes a flat Earth approximation — that North lines are parallel and that "shortest path" coincides with "constant bearing." On the real spherical Earth this breaks down: a path of constant bearing (a rhumb line or loxodrome) spirals toward the pole and is generally longer than the true shortest path (a great-circle route), along which the bearing continuously changes. Reconciling the convenience of constant-bearing steering with the efficiency of great-circle travel is a genuine practical problem in long-distance navigation, addressed in spherical trigonometry. Determining and updating magnetic declination — the shifting difference between magnetic and true North — also remains an active concern, since Earth's magnetic field drifts year by year.
See Also
Trigonometry · Cosine Rule · Sine Rule · Vectors · Angle Measurement · Coordinate Geometry · Parallel Lines and Transversals · Great-Circle Navigation