Kunze Linear Algebra · Problem 6.2.13
Elementary Canonical Forms
Mathematics — Methods · integral-operator-no-characteristic-values
Problem
Let be the vector space of all functions from into which are continuous, i.e., the space of continuous real-valued functions on the real line. Let be the linear operator on defined by Prove that has no characteristic values.Intuitive explanation
The key insight is that characteristic values (eigenvalues) would require a nonzero function satisfying for all and some scalar . Differentiate both sides to relate to itself, then use boundary conditions to derive a contradiction. This shows that no such eigenfunction can exist in the space of continuous functions, no matter what you try.
Intuitive explanation
The key insight is that characteristic values (eigenvalues) would require a nonzero function satisfying for all and some scalar . Differentiate both sides to relate to itself, then use boundary conditions to derive a contradiction. This shows that no such eigenfunction can exist in the space of continuous functions, no matter what you try.