Physics

Physics

Problem

A pipe closed at one end has a length of 0.85 m0.85\,\text{m}. It resonates successively at 300 Hz300\,\text{Hz} and 500 Hz500\,\text{Hz}. Determine the speed of sound in air from these observations. a) 680 m/s680\,\text{m/s} b) 340 m/s340\,\text{m/s} c) 170 m/s170\,\text{m/s} d) 255 m/s255\,\text{m/s}
Intuitive explanation

In a pipe closed at one end, only odd harmonics resonate—the fundamental and its odd multiples. The key insight is that successive resonant frequencies differ by exactly one harmonic step, so you can find which odd harmonics correspond to 300 Hz and 500 Hz, then use the relationship between frequency, pipe length, and sound speed. Once you identify the harmonic numbers, the speed of sound follows directly from v=2fL/nv = 2fL/n.

Intuitive explanation

In a pipe closed at one end, only odd harmonics resonate—the fundamental and its odd multiples. The key insight is that successive resonant frequencies differ by exactly one harmonic step, so you can find which odd harmonics correspond to 300 Hz and 500 Hz, then use the relationship between frequency, pipe length, and sound speed. Once you identify the harmonic numbers, the speed of sound follows directly from v=2fL/nv = 2fL/n.

Browse the problem library