Chemistry

Chemistry

Problem

A student plotted the measured half-life of reactant A (in seconds) versus the initial concentration [A]0[A]_0 (in mol L−1\text{mol}\,\text{L}^{-1}). The data produced a straight line through the origin with a slope of 35 s M−135\,\text{s}\,\text{M}^{-1}. Which value of the rate constant kk is most consistent with the graph? a) 0.020 M s−10.020\,\text{M}\,\text{s}^{-1} b) 0.014 M s−10.014\,\text{M}\,\text{s}^{-1} c) 0.029 M s−10.029\,\text{M}\,\text{s}^{-1} d) 0.0070 M s−10.0070\,\text{M}\,\text{s}^{-1}
Intuitive explanation

The shape of the half-life vs. initial concentration plot tells you the reaction order. For a first-order reaction, t1/2t_{1/2} is independent of [A]0[A]_0 (horizontal line); for second-order, t1/2=1k[A]0t_{1/2} = \frac{1}{k[A]_0} (a line through the origin with slope 1k\frac{1}{k}). Since your graph is a straight line through the origin, you're dealing with second-order kinetics—now just extract kk from the slope using the relationship between half-life and rate constant.

Intuitive explanation

The shape of the half-life vs. initial concentration plot tells you the reaction order. For a first-order reaction, t1/2t_{1/2} is independent of [A]0[A]_0 (horizontal line); for second-order, t1/2=1k[A]0t_{1/2} = \frac{1}{k[A]_0} (a line through the origin with slope 1k\frac{1}{k}). Since your graph is a straight line through the origin, you're dealing with second-order kinetics—now just extract kk from the slope using the relationship between half-life and rate constant.

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