Mathematics

Mathematics

Problem

For p(x)=ex2p(x)=e^{x^{2}}, which of the following is the equation of the line normal to the graph of pp at x=0x=0? a) y=1−xy=1-x b) y=1y=1 c) x=0x=0 d) x=1x=1
Intuitive explanation

The normal line is perpendicular to the tangent, so you need to find the slope of the tangent first using the derivative. Once you have that slope, the normal line's slope is its negative reciprocal. Then use the point-slope form with the point (0,p(0))(0, p(0)) on the curve to write the equation.

Intuitive explanation

The normal line is perpendicular to the tangent, so you need to find the slope of the tangent first using the derivative. Once you have that slope, the normal line's slope is its negative reciprocal. Then use the point-slope form with the point (0,p(0))(0, p(0)) on the curve to write the equation.

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