Physics

Physics

Problem

The gravitational field strength at the surface of a planet of radius RR is gg. A satellite is moving in a circular orbit a distance RR above the surface of the planet. What is the magnitude of the acceleration of the satellite? A. 0 B. g4\frac{g}{4} C. g2\frac{g}{2} D. gg
Intuitive explanation

The key is recognizing that gravitational field strength gg at the surface tells you about the planet's mass, and then using the inverse-square law to find the field strength at a different distance. Since the satellite orbits at distance 2R2R from the planet's center (not RR), the gravitational acceleration there will be weaker by a factor that depends on the ratio of distances squared.

Intuitive explanation

The key is recognizing that gravitational field strength gg at the surface tells you about the planet's mass, and then using the inverse-square law to find the field strength at a different distance. Since the satellite orbits at distance 2R2R from the planet's center (not RR), the gravitational acceleration there will be weaker by a factor that depends on the ratio of distances squared.

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