Mathematics

Mathematics

Problem

If ff and gg are both invertible functions, then (f∘g)−1(f\circ g)^{-1} is equal to a) f−1∘g−1f^{-1}\circ g^{-1} b) g−1∘fg^{-1}\circ f c) g−1∘f−1g^{-1}\circ f^{-1} d) f−1∘gf^{-1}\circ g
Intuitive explanation

When you compose two functions, the inverse "undoes" them in reverse order—think of it like putting on socks then shoes, then removing shoes first, then socks. The key insight is that (f∘g)−1(f \circ g)^{-1} must undo gg first (since it was applied last), then undo ff. This means you're composing the individual inverses, but in the opposite order from the original composition.

Intuitive explanation

When you compose two functions, the inverse "undoes" them in reverse order—think of it like putting on socks then shoes, then removing shoes first, then socks. The key insight is that (f∘g)−1(f \circ g)^{-1} must undo gg first (since it was applied last), then undo ff. This means you're composing the individual inverses, but in the opposite order from the original composition.

Browse the problem library