Problem

Problem

If f(x+ay,x−ay)=axyf(x+ay, x-ay) = axy, then f(x,y)f(x, y) is equal to (a) xyxy (b) x2−a2y2x^2 - a^2 y^2 (c) x2−y24\frac{x^2 - y^2}{4} (d) x2−y2a2\frac{x^2 - y^2}{a^2}
Intuitive explanation

The key is to recognize that ff is defined on a transformed pair of inputs, not the standard (x,y)(x, y) directly. To find the explicit form of ff, treat the arguments u=x+ayu = x + ay and v=x−ayv = x - ay as new variables, then solve for xx and yy in terms of uu and vv. Once you express the right side axyaxy in terms of uu and vv, you'll have f(u,v)f(u, v) in its standard form—which is exactly what f(x,y)f(x, y) equals.

Intuitive explanation

The key is to recognize that ff is defined on a transformed pair of inputs, not the standard (x,y)(x, y) directly. To find the explicit form of ff, treat the arguments u=x+ayu = x + ay and v=x−ayv = x - ay as new variables, then solve for xx and yy in terms of uu and vv. Once you express the right side axyaxy in terms of uu and vv, you'll have f(u,v)f(u, v) in its standard form—which is exactly what f(x,y)f(x, y) equals.

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