Mathematics

Mathematics

Problem

A differentiable function of time is given by F(t)=e5t (1+at2)b,F(t)=e^{5t}\,\bigl(1+a t^{2}\bigr)^{b}, where aa and bb are constants with a>0a>0 and b≠0b\neq0. (a) Compute dFdt\dfrac{dF}{dt} in terms of tt, aa, and bb, leaving your answer factored. (b) Evaluate dFdt\dfrac{dF}{dt} at t=0t=0 and interpret the result in terms of how FF initially changes with time. (c) Holding tt fixed, determine ∂F∂a\dfrac{\partial F}{\partial a} and describe how increasing aa affects F(t)F(t) for a fixed instant t>0t>0. Justify your reasoning.
Intuitive explanation

The key is recognizing that you have a product of two functions, so the product rule is your main tool. The exponential e5te^{5t} has a simple derivative, while (1+at2)b(1+at^2)^b requires the chain rule. Once you differentiate, you'll likely factor out the common exponential term to simplify and reveal the structure of F′(t)F'(t).

Intuitive explanation

The key is recognizing that you have a product of two functions, so the product rule is your main tool. The exponential e5te^{5t} has a simple derivative, while (1+at2)b(1+at^2)^b requires the chain rule. Once you differentiate, you'll likely factor out the common exponential term to simplify and reveal the structure of F′(t)F'(t).

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