Physics

Physics

Problem

Two different metals, X and Y, are illuminated with the same range of light frequencies. Their KmaxK_{\text{max}} versus ff graphs are straight, parallel lines. At a frequency of 8.0×1014 Hz8.0\times10^{14}\,\text{Hz} the measured kinetic energies are 1.5 eV1.5\,\text{eV} for metal X and 0.5 eV0.5\,\text{eV} for metal Y. Which statement about the relative work functions ϕX\phi_X and ϕY\phi_Y is most consistent with these data? a) ϕX\phi_X is larger than ϕY\phi_Y by approximately 1.0 eV1.0\,\text{eV}. b) ϕX\phi_X is smaller than ϕY\phi_Y by approximately 0.5 eV0.5\,\text{eV}. c) ϕX\phi_X is smaller than ϕY\phi_Y by approximately 1.0 eV1.0\,\text{eV}. d) ϕX\phi_X is approximately equal to ϕY\phi_Y.
Intuitive explanation

The photoelectric effect tells us that Kmax=hf−ϕK_{\text{max}} = hf - \phi, so a graph of KmaxK_{\text{max}} versus ff is a straight line with slope hh and y-intercept −ϕ-\phi. Since X and Y have parallel lines, they share the same slope (same hh, obviously), but different y-intercepts—meaning different work functions. At the same frequency, metal X has higher kinetic energy than Y, which means X must have a lower work function: less energy is lost to escape, so more is left over as motion. The difference in KmaxK_{\text{max}} values directly reveals the difference in work functions.

Intuitive explanation

The photoelectric effect tells us that Kmax=hf−ϕK_{\text{max}} = hf - \phi, so a graph of KmaxK_{\text{max}} versus ff is a straight line with slope hh and y-intercept −ϕ-\phi. Since X and Y have parallel lines, they share the same slope (same hh, obviously), but different y-intercepts—meaning different work functions. At the same frequency, metal X has higher kinetic energy than Y, which means X must have a lower work function: less energy is lost to escape, so more is left over as motion. The difference in KmaxK_{\text{max}} values directly reveals the difference in work functions.

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