Problem

Problem

An ant is at a corner of a cubical room of side aa. The ant can move with a constant speed uu. The minimum time taken to reach the farthest corner of the cube is a. 3au\frac{3a}{u} b. 3au\frac{\sqrt{3}a}{u} c. 5au\frac{\sqrt{5}a}{u} d. (2+1)au\frac{(\sqrt{2} + 1)a}{u}
Intuitive explanation

The key is to unfold the cube into a flat net so that the shortest path becomes a straight line. Since the ant must travel on the cube's surface, the farthest corner is diagonally opposite—but the actual shortest route isn't through the interior. By unfolding two adjacent faces, you can see that the straight-line distance on the net is shorter than going along edges, and the minimum time is simply that distance divided by speed uu.

Intuitive explanation

The key is to unfold the cube into a flat net so that the shortest path becomes a straight line. Since the ant must travel on the cube's surface, the farthest corner is diagonally opposite—but the actual shortest route isn't through the interior. By unfolding two adjacent faces, you can see that the straight-line distance on the net is shorter than going along edges, and the minimum time is simply that distance divided by speed uu.

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