Physics

Physics

Problem

For a rigid body of total mass MM, the rotational inertia about an axis located a perpendicular distance dd from an axis that passes through the body’s center of mass is given by which of the following expressions? a) I=Icm−Md2I = I_{cm} - M d^{2} b) I=Icm+12Md2I = I_{cm} + \dfrac{1}{2} M d^{2} c) I=Icm+Md2I = I_{cm} + M d^{2} d) I=Md2I = M d^{2}
Intuitive explanation

This is the parallel axis theorem, which connects rotational inertia about two different axes. The key insight is that rotating about an off-center axis is equivalent to rotating about the center of mass plus the effect of the entire mass concentrated at that distance—so you add a term Md2Md^2 to account for the "extra" rotational resistance from being farther away. Think of it as: inertia shifts outward when you move the rotation axis away from the center.

Intuitive explanation

This is the parallel axis theorem, which connects rotational inertia about two different axes. The key insight is that rotating about an off-center axis is equivalent to rotating about the center of mass plus the effect of the entire mass concentrated at that distance—so you add a term Md2Md^2 to account for the "extra" rotational resistance from being farther away. Think of it as: inertia shifts outward when you move the rotation axis away from the center.

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