Mathematics

The key is to simplify the radicals by factoring out perfect squares, then multiply and reduce. Notice that $\sqrt{75} = \sqrt{25 \cdot 3} = 5\sqrt{3}$ and $\sqrt{12} = \sqrt{4 \cdot 3} = 2\sqrt{3}$, so their product becomes much cleaner. Once you multiply and cancel, you'll get a number with no radicals left—which tells you exactly which familiar number set it belongs to.

The key is to simplify the radicals by factoring out perfect squares, then multiply and reduce. Notice that $\sqrt{75} = \sqrt{25 \cdot 3} = 5\sqrt{3}$ and $\sqrt{12} = \sqrt{4 \cdot 3} = 2\sqrt{3}$, so their product becomes much cleaner. Once you multiply and cancel, you'll get a number with no radicals left—which tells you exactly which familiar number set it belongs to.