Mathematics

Mathematics

Problem

Consider a twice–differentiable function ff whose derivative is given by f′(x)=(x−1)2(x+2)f'(x)=(x-1)^2(x+2). Which of the following statements must be true? a) ff has a relative maximum at x=−2x=-2 and points of inflection at x=−1x=-1 and x=1x=1. b) ff has no relative extrema because f′(x)f'(x) is always nonnegative. c) ff has a relative minimum at x=−2x=-2 and points of inflection at x=−1x=-1 and x=1x=1. d) ff has a relative maximum at x=1x=1 and is concave down for x>1x>1.
Intuitive explanation

The key is to recognize that f′(x)f'(x) tells you where ff is increasing or decreasing, and where its concavity changes. Notice that f′(x)f'(x) has a double root at x=1x=1 and a simple root at x=−2x=-2—this means ff touches the xx-axis at x=1x=1 without crossing it (so x=1x=1 is neither a local max nor min), while f′f' actually changes sign at x=−2x=-2. Use a sign chart on f′(x)f'(x) to determine monotonicity, and then analyze f′′(x)f''(x) to find inflection points where concavity flips.

Intuitive explanation

The key is to recognize that f′(x)f'(x) tells you where ff is increasing or decreasing, and where its concavity changes. Notice that f′(x)f'(x) has a double root at x=1x=1 and a simple root at x=−2x=-2—this means ff touches the xx-axis at x=1x=1 without crossing it (so x=1x=1 is neither a local max nor min), while f′f' actually changes sign at x=−2x=-2. Use a sign chart on f′(x)f'(x) to determine monotonicity, and then analyze f′′(x)f''(x) to find inflection points where concavity flips.

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