Mathematics

Mathematics

Problem

Which of the following limits can be evaluated merely by substituting x=1x=1? a) lim⁡x→1sin⁡(x−1)x−1\displaystyle \lim_{x\to 1}\dfrac{\sin(x-1)}{x-1} b) lim⁡x→12x+3\displaystyle \lim_{x\to 1} \sqrt{2x+3} c) lim⁡x→1x3−1x−1\displaystyle \lim_{x\to 1}\dfrac{x^{3}-1}{x-1} d) lim⁡x→1x−1\displaystyle \lim_{x\to 1}\sqrt{x-1}
Intuitive explanation

The key insight is recognizing when direct substitution is safe—that is, when plugging in x=1x=1 won't create an undefined expression like 00\frac{0}{0} or k0\frac{k}{0}. A limit is evaluable by substitution alone if the function is continuous at that point, meaning the numerator and denominator are both well-defined and the denominator is nonzero. Before you check each option, ask yourself: "Does this expression stay defined and finite when I plug in x=1x=1?" If yes, substitute; if no, you'll need algebra or another technique first.

Intuitive explanation

The key insight is recognizing when direct substitution is safe—that is, when plugging in x=1x=1 won't create an undefined expression like 00\frac{0}{0} or k0\frac{k}{0}. A limit is evaluable by substitution alone if the function is continuous at that point, meaning the numerator and denominator are both well-defined and the denominator is nonzero. Before you check each option, ask yourself: "Does this expression stay defined and finite when I plug in x=1x=1?" If yes, substitute; if no, you'll need algebra or another technique first.

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