Mathematics

Mathematics

Problem

The length of longer diagonal of the parallelogram constructed on 5a+2b5\mathbf{a}+2\mathbf{b} and a−3b\mathbf{a}-3\mathbf{b}, when it is given that ∣a∣=22|\mathbf{a}|=2\sqrt{2}, ∣b∣=3|\mathbf{b}|=3 and angle between a\mathbf{a} and b\mathbf{b} is π4\frac{\pi}{4}, is a. 15 b. 113\sqrt{113} c. 593\sqrt{593} d. 369\sqrt{369}
Intuitive explanation

When you construct a parallelogram from two vectors as adjacent sides, the diagonals are their sum and difference. Here, you need to find both diagonals of the parallelogram with sides 5a+2b5\mathbf{a}+2\mathbf{b} and a−3b\mathbf{a}-3\mathbf{b}, then identify which is longer by computing their magnitudes using the dot product formula ∣v∣2=v⋅v|\mathbf{v}|^2 = \mathbf{v} \cdot \mathbf{v}.

Intuitive explanation

When you construct a parallelogram from two vectors as adjacent sides, the diagonals are their sum and difference. Here, you need to find both diagonals of the parallelogram with sides 5a+2b5\mathbf{a}+2\mathbf{b} and a−3b\mathbf{a}-3\mathbf{b}, then identify which is longer by computing their magnitudes using the dot product formula ∣v∣2=v⋅v|\mathbf{v}|^2 = \mathbf{v} \cdot \mathbf{v}.

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