Mathematics

Mathematics

Problem

The sum of all the real solutions of equation log⁡(x+3)(6x2+28x+30)=5−2log⁡(6x+10)(x2+6x+9)\log_{(x+3)}(6x^2 + 28x + 30) = 5 - 2\log_{(6x+10)}(x^2 + 6x + 9) is :
Intuitive explanation

This problem hinges on recognizing that both logarithmic expressions can be simplified by factoring their arguments. Notice that 6x2+28x+306x^2 + 28x + 30 and x2+6x+9x^2 + 6x + 9 are perfect squares or products of linear factors, and the bases x+3x+3 and 6x+106x+10 are related to those factors. Once you rewrite each logarithm in terms of simpler bases, the equation collapses into something much more manageable—often a polynomial you can solve directly. The key is careful algebraic manipulation before attempting to isolate xx.

Intuitive explanation

This problem hinges on recognizing that both logarithmic expressions can be simplified by factoring their arguments. Notice that 6x2+28x+306x^2 + 28x + 30 and x2+6x+9x^2 + 6x + 9 are perfect squares or products of linear factors, and the bases x+3x+3 and 6x+106x+10 are related to those factors. Once you rewrite each logarithm in terms of simpler bases, the equation collapses into something much more manageable—often a polynomial you can solve directly. The key is careful algebraic manipulation before attempting to isolate xx.

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