Problem

Problem

(i) P+C(carbon)+Cl2⟶Q+CO↑P + C(\text{carbon}) + \text{Cl}_2 \longrightarrow Q + \text{CO} \uparrow (ii) Q+H2O⟶R+HClQ + \text{H}_2\text{O} \longrightarrow R + \text{HCl} (iii) BN+H2O⟶R+NH3↑\text{BN} + \text{H}_2\text{O} \longrightarrow R + \text{NH}_3 \uparrow (iv) Q+LiAlH4⟶S+LiCl+AlCl3Q + \text{LiAlH}_4 \longrightarrow S + \text{LiCl} + \text{AlCl}_3 (v) S+H2⟶R+H2↑S + \text{H}_2\longrightarrow R + \text{H}_2 \uparrow (vi) S+NaH⟶TS + \text{NaH} \longrightarrow T Compound Q has: (I) zero dipole moment (II) a planar trigonal structure (III) an electron deficient compound (IV) a Lewis base a. I, IV b. I, II, IV c. I, II, III d. I, II, III, IV
Intuitive explanation

This is a detective problem where you work backward from the clues about compound QQ to identify the entire reaction sequence. The key insight is that QQ must satisfy all four properties simultaneously—especially that it's planar, nonpolar, electron-deficient, and still basic enough to accept hydride from LiAlH4\text{LiAlH}_4. Once you identify QQ, the other compounds fall into place by tracking what happens when you add water, reduce with hydride, or react with strong bases. Think about which common compounds fit a planar trigonal structure with zero dipole moment.

Intuitive explanation

This is a detective problem where you work backward from the clues about compound QQ to identify the entire reaction sequence. The key insight is that QQ must satisfy all four properties simultaneously—especially that it's planar, nonpolar, electron-deficient, and still basic enough to accept hydride from LiAlH4\text{LiAlH}_4. Once you identify QQ, the other compounds fall into place by tracking what happens when you add water, reduce with hydride, or react with strong bases. Think about which common compounds fit a planar trigonal structure with zero dipole moment.

Browse the problem library