Physics

Physics

Problem

A light beam of wavelength 600 nm in air passes through film 1 (n1=1.2n_1 = 1.2) of thickness 1.0μm1.0 \mu\text{m}, then through film 2 (air) of thickness 1.5μm1.5 \mu\text{m}, and finally through film 3 (n3=1.8n_3 = 1.8) of thickness 1.0μm1.0 \mu\text{m}. a. Which film does the light cross in the least time, and what is that least time? b. What are the total number of wavelengths (at any instant) across all three films together?
Intuitive explanation

The key is tracking how the wavelength changes as light moves between media with different refractive indices, then counting how many wavelengths fit into each layer—this determines the total phase accumulated. When light travels through a medium with refractive index nn, its wavelength shrinks to λ/n\lambda/n, so a thickness dd contains nd/λnd/\lambda wavelengths. Sum these across all three layers to find the total optical path length, which tells you whether the beam emerges in phase or out of phase with itself.

Intuitive explanation

The key is tracking how the wavelength changes as light moves between media with different refractive indices, then counting how many wavelengths fit into each layer—this determines the total phase accumulated. When light travels through a medium with refractive index nn, its wavelength shrinks to λ/n\lambda/n, so a thickness dd contains nd/λnd/\lambda wavelengths. Sum these across all three layers to find the total optical path length, which tells you whether the beam emerges in phase or out of phase with itself.

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