Student Friendly Introduction to QFT · Problem 10

Interactions: The Underlying Theory

Physics — QFT · lagrangian-symmetry-spring-particle

Problem

For a particle attached to a spring confined to move in one dimension, the potential energy V=12k(x1)2V = \frac{1}{2}k(x^1)^2. Use this to find the Lagrangian of this system. Is this Lagrangian symmetric with respect to translations of x1x^1? Is momentum conserved in the x1x^1 direction? Find the equation of motion for the system using the Lagrangian approach. What does the momentum equal? Is this Lagrangian symmetric in x2x^2? Is momentum conserved in the x2x^2 direction? Does this make sense physically?
Intuitive explanation

The Lagrangian is the kinetic energy minus potential energy, L=T−VL = T - V, and it encodes all the dynamics of a system. Symmetries of the Lagrangian directly tell you which quantities are conserved via Noether's theorem: if LL doesn't change when you shift a coordinate, momentum in that direction is conserved. Here you'll see that the spring potential breaks translation symmetry in x1x^1 (the direction of motion), so momentum isn't conserved—but x2x^2 (a direction the particle can't move in) has no forces, so translation symmetry and momentum conservation hold there, which is physically sensible.

Intuitive explanation

The Lagrangian is the kinetic energy minus potential energy, L=T−VL = T - V, and it encodes all the dynamics of a system. Symmetries of the Lagrangian directly tell you which quantities are conserved via Noether's theorem: if LL doesn't change when you shift a coordinate, momentum in that direction is conserved. Here you'll see that the spring potential breaks translation symmetry in x1x^1 (the direction of motion), so momentum isn't conserved—but x2x^2 (a direction the particle can't move in) has no forces, so translation symmetry and momentum conservation hold there, which is physically sensible.

Related theory

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