Mathematics

Mathematics

Problem

Which of the following is an exact expression for cos⁡2θ\cos 2\theta? a) 1−2sin⁡θ1-2\sin\theta b) 2sin⁡θcos⁡θ2\sin\theta\cos\theta c) cos⁡2θ−sin⁡2θ\cos^{2}\theta-\sin^{2}\theta d) 2sin⁡2θ−12\sin^{2}\theta-1
Intuitive explanation

The key is recognizing that the double-angle formula for cosine comes in three equivalent forms, each useful depending on what you already know. Rather than memorizing one version, understand that cos⁡2θ\cos 2\theta can be expressed using cos⁡2θ\cos^2 \theta, sin⁡2θ\sin^2 \theta, or both—and you can derive whichever form you need from the Pythagorean identity sin⁡2θ+cos⁡2θ=1\sin^2 \theta + \cos^2 \theta = 1. This flexibility is what makes double-angle formulas so powerful.

Intuitive explanation

The key is recognizing that the double-angle formula for cosine comes in three equivalent forms, each useful depending on what you already know. Rather than memorizing one version, understand that cos⁡2θ\cos 2\theta can be expressed using cos⁡2θ\cos^2 \theta, sin⁡2θ\sin^2 \theta, or both—and you can derive whichever form you need from the Pythagorean identity sin⁡2θ+cos⁡2θ=1\sin^2 \theta + \cos^2 \theta = 1. This flexibility is what makes double-angle formulas so powerful.

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