Physics

Physics

Problem

Two horizontal forces act on a small ring. • Force 1: magnitude 10 N10\,\text{N} directed 30∘30^{\circ} above the positive xx-axis. • Force 2: magnitude 8 N8\,\text{N} directed 120∘120^{\circ} counter-clockwise from the positive xx-axis. Determine the magnitude and direction (angle measured counter-clockwise from the positive xx-axis) of a single additional horizontal force that will keep the ring in static equilibrium.
Intuitive explanation

The key to equilibrium is that all forces must sum to zero—so your third force must exactly cancel the net effect of the first two. Resolve each given force into xx and yy components, add them to find the resultant, then recognize that the equilibrium force is simply the negative of that resultant (opposite magnitude, opposite direction). This transforms a geometry problem into straightforward component arithmetic.

Intuitive explanation

The key to equilibrium is that all forces must sum to zero—so your third force must exactly cancel the net effect of the first two. Resolve each given force into xx and yy components, add them to find the resultant, then recognize that the equilibrium force is simply the negative of that resultant (opposite magnitude, opposite direction). This transforms a geometry problem into straightforward component arithmetic.

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