Introduction to Electrodynamics · Problem 1.27

Vector Analysis — David J. Griffiths

Physics · vector-calculus-second-derivatives

Problem

Prove that the divergence of a curl is always zero. Check it for function va\mathbf{v}_a in Prob. 1.15.
Intuitive explanation

The key insight is that curl and divergence are differential operators with a special relationship: taking the curl of any vector field produces a field whose divergence must vanish due to the symmetry of mixed partial derivatives. Rather than memorizing this identity, you can verify it by expanding ∇⋅(∇×v)\nabla \cdot (\nabla \times \mathbf{v}) in component form—the cross-derivatives will cancel in pairs, leaving zero. This is a beautiful example of how vector calculus identities emerge naturally from calculus itself.

Intuitive explanation

The key insight is that curl and divergence are differential operators with a special relationship: taking the curl of any vector field produces a field whose divergence must vanish due to the symmetry of mixed partial derivatives. Rather than memorizing this identity, you can verify it by expanding ∇⋅(∇×v)\nabla \cdot (\nabla \times \mathbf{v}) in component form—the cross-derivatives will cancel in pairs, leaving zero. This is a beautiful example of how vector calculus identities emerge naturally from calculus itself.

Related theory

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