Physics
Physics
Problem
Two ideal batteries and a single resistor of resistance form a simple loop in the order: Battery A, resistor, Battery B. Battery A supplies and is oriented so that its positive terminal is on the left side of the resistor. Battery B supplies and is oriented so that its positive terminal is on the right side of the resistor, opposing Battery A. Which option gives the direction of conventional current through the resistor and the current’s magnitude? a) Left to right; b) Right to left; c) Left to right; d) No current; the opposing batteries exactly cancel each other.Intuitive explanation
This is about applying Kirchhoff's voltage law to find net voltage and current direction in a loop. The key insight is that batteries push current in opposite directions here, so you subtract their voltages to find the net "push" around the loop. The battery with the larger voltage wins, determining current direction, and Ohm's law then gives you the magnitude.
Intuitive explanation
This is about applying Kirchhoff's voltage law to find net voltage and current direction in a loop. The key insight is that batteries push current in opposite directions here, so you subtract their voltages to find the net "push" around the loop. The battery with the larger voltage wins, determining current direction, and Ohm's law then gives you the magnitude.