Chemistry

Chemistry

Problem

If a balanced thermochemical equation is multiplied by 3, what happens to the reported value of ΔH∘\Delta H^\circ for the reaction?
Intuitive explanation

When you multiply a balanced equation by 3, you're tripling the amount of reactants and products involved—so the total heat released or absorbed also triples. The key insight is that ΔH∘\Delta H^\circ is an extensive property: it scales with the quantity of reaction. Think of it like doubling a recipe; you don't just make twice as much food, you also use twice as much energy to cook it. So if the original ΔH∘\Delta H^\circ was −100-100 kJ, multiplying the equation by 3 gives 3×(−100)=−3003 \times (-100) = -300 kJ.

Intuitive explanation

When you multiply a balanced equation by 3, you're tripling the amount of reactants and products involved—so the total heat released or absorbed also triples. The key insight is that ΔH∘\Delta H^\circ is an extensive property: it scales with the quantity of reaction. Think of it like doubling a recipe; you don't just make twice as much food, you also use twice as much energy to cook it. So if the original ΔH∘\Delta H^\circ was −100-100 kJ, multiplying the equation by 3 gives 3×(−100)=−3003 \times (-100) = -300 kJ.

Browse the problem library