Physics

Physics

Problem

Stone A is dropped from the top of a 60 m60\,\text{m} high cliff. One second later, stone B is thrown vertically downward from the same point so that both stones reach the ground simultaneously. Neglect air resistance and take g=10 m/s2g = 10\,\text{m/s}^2. a. (a) If stone A takes t st\,\text{s} to reach the ground from the moment it is released, express the time of flight of stone B in terms of tt. b. (b) Calculate the initial speed with which stone B must be thrown downward so that both stones hit the ground together. c. (c) Find the distance between the two stones 0.5 s0.5\,\text{s} after B is released.
Intuitive explanation

This is a kinematics problem about coordinating two different motions to meet at the same place and time. The key insight is that stone A gets a 1-second head start with zero initial velocity, so you need to find how far it falls in that first second, then use the remaining distance and time to work backward and find stone B's required initial velocity. Both stones must travel their respective distances in their respective times—set up position equations for each and use the constraint that they hit ground simultaneously.

Intuitive explanation

This is a kinematics problem about coordinating two different motions to meet at the same place and time. The key insight is that stone A gets a 1-second head start with zero initial velocity, so you need to find how far it falls in that first second, then use the remaining distance and time to work backward and find stone B's required initial velocity. Both stones must travel their respective distances in their respective times—set up position equations for each and use the constraint that they hit ground simultaneously.

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