Mathematics

Mathematics

Problem

Describe the sign of y′′y'' on (0,∞)(0,\infty) for y=arctan⁡xy=\arctan x, and state what this implies about the graph’s concavity over that interval.
Intuitive explanation

The key is to find the second derivative and determine its sign. Start by computing y′=11+x2y' = \frac{1}{1+x^2}, then differentiate again to get y′′y''. Since x>0x > 0, you'll see that y′′y'' is always negative—this means the curve bends downward everywhere on (0,∞)(0,\infty), so the graph is concave down. Concavity tells you how the slope itself is changing: a negative second derivative means the function is increasing, but at a decreasing rate.

Intuitive explanation

The key is to find the second derivative and determine its sign. Start by computing y′=11+x2y' = \frac{1}{1+x^2}, then differentiate again to get y′′y''. Since x>0x > 0, you'll see that y′′y'' is always negative—this means the curve bends downward everywhere on (0,∞)(0,\infty), so the graph is concave down. Concavity tells you how the slope itself is changing: a negative second derivative means the function is increasing, but at a decreasing rate.

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