Light Intensity in 2D Flatland · CAP 2017 #4

Physics · optics

Problem

The creatures of flatland inhabit a 2-dimensional world. Square, a man of good standing in flatland, holds a hot candle which emits light of intensity 36 Watts. 3 metres away, a detector feels: a) 6π\frac{6}{\pi} W/m b) 1π\frac{1}{\pi} W/m² c) 6π\frac{6}{\pi} W/m² d) 1π\frac{1}{\pi} W/m e) 6π\frac{6}{\pi} W
Intuitive explanation

In flatland's 2D world, light spreads differently than in our 3D reality. Instead of spreading over a sphere's surface (proportional to r2r^2), the intensity spreads over a circle's circumference (proportional to rr). You need to apply the inverse-square law's 2D cousin: intensity falls off as 1/r1/r, and the "area" receiving light is actually a 1D line segment. This shifts which answer has which units—think carefully about what "intensity per unit length" means in a flat world.

Intuitive explanation

In flatland's 2D world, light spreads differently than in our 3D reality. Instead of spreading over a sphere's surface (proportional to r2r^2), the intensity spreads over a circle's circumference (proportional to rr). You need to apply the inverse-square law's 2D cousin: intensity falls off as 1/r1/r, and the "area" receiving light is actually a 1D line segment. This shifts which answer has which units—think carefully about what "intensity per unit length" means in a flat world.

Related theory

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