Physics

Physics

Problem

In the expression y=Asin⁡(kx−ωt)y = A\sin(kx - \omega t) for a progressive sinusoidal wave, the wavelength λ\lambda is related to the wave number kk by a) λ=1k\lambda = \dfrac{1}{k} b) λ=2πk\lambda = \dfrac{2\pi}{k} c) λ=πk\lambda = \dfrac{\pi}{k} d) λ=4πk\lambda = \dfrac{4\pi}{k}
Intuitive explanation

The wave number kk is really a measure of how many radians of oscillation fit into one unit of distance—it's the spatial equivalent of angular frequency ω\omega. To find the relationship, think about what happens when the wave completes exactly one full cycle: the argument of the sine function changes by 2π2\pi radians as you move one wavelength λ\lambda in space. Setting kλ=2πk\lambda = 2\pi directly gives you the connection between these two parameters.

Intuitive explanation

The wave number kk is really a measure of how many radians of oscillation fit into one unit of distance—it's the spatial equivalent of angular frequency ω\omega. To find the relationship, think about what happens when the wave completes exactly one full cycle: the argument of the sine function changes by 2π2\pi radians as you move one wavelength λ\lambda in space. Setting kλ=2πk\lambda = 2\pi directly gives you the connection between these two parameters.

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