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Chemistry
Chemistry
Problem
The enthalpy change (
Δ
H
\Delta H
Δ
H
) for the reaction,
N
2
(
g
)
+
3
H
2
(
g
)
⟶
2
NH
3
(
g
)
\text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \longrightarrow 2\text{NH}_3(\text{g})
N
2
(
g
)
+
3
H
2
(
g
)
⟶
2
NH
3
(
g
)
is
−
92.38
kJ
-92.38\ \text{kJ}
−
92.38
kJ
at
298
K
298\ \text{K}
298
K
. What is
Δ
U
\Delta U
Δ
U
at
298
K
298\ \text{K}
298
K
?
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