Algebraic Topology · Problem 2.2.36

Homology — Allen Hatcher

Mathematics — Topology · homology-product-spaces

Problem

Show that Hi(X×Sn)≈Hi(X)⊕Hi−n(X)H_i(X \times S^n) \approx H_i(X) \oplus H_{i-n}(X) for all ii and nn, where Hi=0H_i = 0 for i<0i < 0 by definition. Namely, show Hi(X×Sn)≈Hi(X)⊕Hi(X×Sn,X×{x0})H_i(X \times S^n) \approx H_i(X) \oplus H_i(X \times S^n, X \times \{x_0\}) and Hi(X×Sn,X×{x0})≈Hi−1(X×Sn−1,X×{x0})H_i(X \times S^n, X \times \{x_0\}) \approx H_{i-1}(X \times S^{n-1}, X \times \{x_0\}). [For the latter isomorphism the relative Mayer--Vietoris sequence yields an easy proof.]
Intuitive explanation

The key is to use the long exact sequence of the pair and Mayer–Vietoris to peel away one dimension of the sphere at a time. Start by splitting SnS^n into two hemispheres; their overlap is Sn−1S^{n-1}, which lets Mayer–Vietoris relate homology of X×SnX \times S^n to that of X×Sn−1X \times S^{n-1}. By induction and the relative sequence, you'll see that each sphere dimension contributes a copy of H∗(X)H_*(X) shifted by one degree, building up the direct sum formula.

Intuitive explanation

The key is to use the long exact sequence of the pair and Mayer–Vietoris to peel away one dimension of the sphere at a time. Start by splitting SnS^n into two hemispheres; their overlap is Sn−1S^{n-1}, which lets Mayer–Vietoris relate homology of X×SnX \times S^n to that of X×Sn−1X \times S^{n-1}. By induction and the relative sequence, you'll see that each sphere dimension contributes a copy of H∗(X)H_*(X) shifted by one degree, building up the direct sum formula.

Related theory

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