Physics

Physics

Problem

Velocity of the river with respect to ground is given by v0v_0. Width of the river is dd. A swimmer swims (with respect to water) perpendicular to the current with acceleration a=2ta = 2t (where tt is time) starting from rest from the origin OO at t=0t = 0. The equation of trajectory of the path followed by the swimmer is (A) y=x33v03y = \frac{x^3}{3v_0^3} (B) y=x22v02y = \frac{x^2}{2v_0^2} (C) y=xv0y = \frac{x}{v_0} (D) y=xv0y = \sqrt{\frac{x}{v_0}}
Intuitive explanation

The key is recognizing that the swimmer's motion has two independent components: perpendicular to the current (where acceleration varies with time) and parallel to it (where the river carries them at constant v0v_0). Find the swimmer's velocity and position perpendicular to the current by integrating the time-dependent acceleration, then use the constant drift from the river current to eliminate time and relate the two position coordinates—that's your trajectory equation.

Intuitive explanation

The key is recognizing that the swimmer's motion has two independent components: perpendicular to the current (where acceleration varies with time) and parallel to it (where the river carries them at constant v0v_0). Find the swimmer's velocity and position perpendicular to the current by integrating the time-dependent acceleration, then use the constant drift from the river current to eliminate time and relate the two position coordinates—that's your trajectory equation.

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