Chemistry

Chemistry

Problem

The decomposition of equal mole of two reactants PP and QQ obey I order kinetics with half life 54 and 18 minute respectively. If both are allowed to run for 54 minute. The ratio of mole of PP and QQ left after decomposition will be.
Intuitive explanation

First-order decomposition means each substance decays independently at its own rate, determined by its half-life. The key insight is that after time tt, the fraction remaining follows N(t)=N0⋅(1/2)t/t1/2N(t) = N_0 \cdot (1/2)^{t/t_{1/2}}. Since PP and QQ have different half-lives, they'll decompose at different speeds over the same 54-minute period—count how many half-lives each completes to find what fraction survives.

Intuitive explanation

First-order decomposition means each substance decays independently at its own rate, determined by its half-life. The key insight is that after time tt, the fraction remaining follows N(t)=N0⋅(1/2)t/t1/2N(t) = N_0 \cdot (1/2)^{t/t_{1/2}}. Since PP and QQ have different half-lives, they'll decompose at different speeds over the same 54-minute period—count how many half-lives each completes to find what fraction survives.

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