Mathematics

Mathematics

Problem

Let a,ba, b and cc be three consecutive terms of an arithmetic progression. a. Prove that 2b=a+c2b = a + c. b. Using the result of part (i), determine whether the numbers 3,7,123, 7, 12 can be consecutive terms of an arithmetic progression. Give reasons for your answer. c. If p−4,2p+1p - 4, 2p + 1 and 5p−95p - 9 are consecutive terms of an arithmetic progression, find the value of pp and write the three terms in increasing order.
Intuitive explanation

The key insight is that in an arithmetic progression, the middle term is always the average of its neighbors. This means if you know aa, bb, and cc are consecutive, you can write a single equation relating them: b=a+c2b = \frac{a+c}{2}, or equivalently 2b=a+c2b = a + c. This relationship is your anchor—use it to simplify whatever the problem asks you to prove or find.

Intuitive explanation

The key insight is that in an arithmetic progression, the middle term is always the average of its neighbors. This means if you know aa, bb, and cc are consecutive, you can write a single equation relating them: b=a+c2b = \frac{a+c}{2}, or equivalently 2b=a+c2b = a + c. This relationship is your anchor—use it to simplify whatever the problem asks you to prove or find.

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