Mathematics

Mathematics

Problem

The function gg is the first derivative of a differentiable function ff. A verbal description of the graph of gg is provided. • g(x)=0g(x)=0 at x=−3x=-3, x=0x=0, and x=4x=4. • g(x)<0g(x)<0 for x<−3x<-3. • g(x)>0g(x)>0 for −3<x<0-3<x<0. • g(x)<0g(x)<0 for x<4x<4 and x>0x>0 is a misprint. However, according to the original text, it should read: g(x)<0g(x)<0 for 0<x<40<x<4. • g(x)>0g(x)>0 for x>4x>4. • gg is continuous everywhere. Based solely on this information about gg, analyze the behavior of ff. a. Part 1: (a) Determine the open intervals on which ff is increasing and the open intervals on which ff is decreasing. Explain your reasoning. b. Part 2: (b) Identify all xx-coordinates of local extrema of ff and state whether each is a local maximum or a local minimum. Justify each classification. c. Part 3: (c) Describe how the concavity of ff might behave near x=−3x=-3, x=0x=0, and x=4x=4, even though no information about g′g' is given. Your answer should be qualitative rather than computational.
Intuitive explanation

Since gg is the derivative of ff, the zeros and sign of gg tell you exactly where ff has horizontal tangents and whether ff is increasing or decreasing. Where g>0g > 0, the function ff is climbing; where g<0g < 0, it's falling. The sign changes at x=−3,0,4x = -3, 0, 4 mark local extrema—use the sign pattern before and after each zero to determine whether each is a local maximum or minimum.

Intuitive explanation

Since gg is the derivative of ff, the zeros and sign of gg tell you exactly where ff has horizontal tangents and whether ff is increasing or decreasing. Where g>0g > 0, the function ff is climbing; where g<0g < 0, it's falling. The sign changes at x=−3,0,4x = -3, 0, 4 mark local extrema—use the sign pattern before and after each zero to determine whether each is a local maximum or minimum.

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