Chemistry
Chemistry
Problem
0.04 M solution of ( ) is diluted to reduce its molar concentration to half. The change in during dilution is : a. +0.1615 b. -0.1615 c. +0.2615 d. -0.2615Intuitive explanation
When you dilute a weak base, its ionization equilibrium shifts—the base ionizes more to partially offset the concentration drop. The key is recognizing that stays constant, so you need to recalculate the at each concentration using the equilibrium expression, then convert both to values. The difference tells you how much the actually changes, which is always less than you'd predict from concentration alone.
Intuitive explanation
When you dilute a weak base, its ionization equilibrium shifts—the base ionizes more to partially offset the concentration drop. The key is recognizing that stays constant, so you need to recalculate the at each concentration using the equilibrium expression, then convert both to values. The difference tells you how much the actually changes, which is always less than you'd predict from concentration alone.