Chemistry

Chemistry

Problem

0.04 M solution of CH3NH2\text{CH}_3\text{NH}_2 ( pKb=3.3010\text{p}K_b = 3.3010 ) is diluted to reduce its molar concentration to half. The change in pH\text{pH} during dilution is : a. +0.1615 b. -0.1615 c. +0.2615 d. -0.2615
Intuitive explanation

When you dilute a weak base, its ionization equilibrium shifts—the base ionizes more to partially offset the concentration drop. The key is recognizing that KbK_b stays constant, so you need to recalculate the [OH−][\text{OH}^-] at each concentration using the equilibrium expression, then convert both to pH\text{pH} values. The difference tells you how much the pH\text{pH} actually changes, which is always less than you'd predict from concentration alone.

Intuitive explanation

When you dilute a weak base, its ionization equilibrium shifts—the base ionizes more to partially offset the concentration drop. The key is recognizing that KbK_b stays constant, so you need to recalculate the [OH−][\text{OH}^-] at each concentration using the equilibrium expression, then convert both to pH\text{pH} values. The difference tells you how much the pH\text{pH} actually changes, which is always less than you'd predict from concentration alone.

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