Physics

Physics

Problem

A closed cubical box of side length LL is exactly half-filled with an ideal liquid of density ρ\rho. The box is accelerated horizontally with a constant acceleration a=ga=g. Find the pressure difference between the top rear corner and the bottom front corner of the box.
Intuitive explanation

When a container of liquid accelerates, the liquid surface tilts because the effective gravity shifts—it's no longer purely vertical, but now points at an angle combining real gravity gg downward with the pseudo-force aa backward. The pressure difference between any two points depends on the height difference measured along this new effective gravity direction. You'll need to find how the liquid surface reorients, then calculate the vertical height difference between your two corners to apply the hydrostatic pressure formula ΔP=ρgΔh\Delta P = \rho g \Delta h.

Intuitive explanation

When a container of liquid accelerates, the liquid surface tilts because the effective gravity shifts—it's no longer purely vertical, but now points at an angle combining real gravity gg downward with the pseudo-force aa backward. The pressure difference between any two points depends on the height difference measured along this new effective gravity direction. You'll need to find how the liquid surface reorients, then calculate the vertical height difference between your two corners to apply the hydrostatic pressure formula ΔP=ρgΔh\Delta P = \rho g \Delta h.

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