Mathematics

Mathematics

Problem

An arithmetic progression has first term 77. Its nn-th term is 3333, and the sum of its first nn terms is 220220. Determine nn. a) 1010 b) 1212 c) 1111 d) 99
Intuitive explanation

You have two unknowns (nn and the common difference dd) and two equations: one from the nn-th term formula and one from the sum formula. The key insight is that the sum of an arithmetic progression depends on both the first and last terms—so use Sn=n(a1+an)2S_n = \frac{n(a_1 + a_n)}{2} to connect what you know directly, then solve for nn without finding dd first.

Intuitive explanation

You have two unknowns (nn and the common difference dd) and two equations: one from the nn-th term formula and one from the sum formula. The key insight is that the sum of an arithmetic progression depends on both the first and last terms—so use Sn=n(a1+an)2S_n = \frac{n(a_1 + a_n)}{2} to connect what you know directly, then solve for nn without finding dd first.

Browse the problem library