Linear Algebra Done Right · Problem 8A.25

Operators on Complex Vector Spaces — Sheldon Axler

Mathematics — Linear Algebra · nilpotent-operators-orthonormal

Problem

Suppose that VV is an inner product space and T∈L(V)T \in \mathcal{L}(V) is nilpotent. Show that there is an orthonormal basis of VV with respect to which the matrix of TT has the upper-triangular form promised by 8.18(c).
Intuitive explanation

The key insight is that nilpotent operators are automatically normal when restricted to invariant subspaces, which lets you apply the spectral theorem machinery. Since TT is nilpotent, all its eigenvalues are zero, so the upper-triangular form collapses to strictly upper-triangular. Build your orthonormal basis inductively: find an eigenvector (which exists because TT is nilpotent), orthonormalize it, then work on the orthogonal complement where TT still acts nilpotently, repeating until done.

Intuitive explanation

The key insight is that nilpotent operators are automatically normal when restricted to invariant subspaces, which lets you apply the spectral theorem machinery. Since TT is nilpotent, all its eigenvalues are zero, so the upper-triangular form collapses to strictly upper-triangular. Build your orthonormal basis inductively: find an eigenvector (which exists because TT is nilpotent), orthonormalize it, then work on the orthogonal complement where TT still acts nilpotently, repeating until done.

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