Linear Algebra Done Right · Problem 8A.9

Operators on Complex Vector Spaces — Sheldon Axler

Mathematics — Linear Algebra · null-spaces-range-powers

Problem

Suppose T∈L(V)T \in \mathcal{L}(V) and mm is a nonnegative integer. Prove that null⁡Tm=null⁡Tm+1  ⟺  range⁡Tm=range⁡Tm+1.\operatorname{null} T^m = \operatorname{null} T^{m+1} \iff \operatorname{range} T^m = \operatorname{range} T^{m+1}.
Intuitive explanation

This problem asks you to connect two seemingly opposite properties of powers of a linear operator: when the kernel stops growing and when the range stops shrinking. The key insight is that null⁡Tm\operatorname{null} T^m and range⁡Tm\operatorname{range} T^m are dual notions—one measures what TmT^m "kills," the other what it "reaches"—and they're constrained by the rank-nullity theorem applied repeatedly. If the null space stabilizes at step mm, the rank can't grow further, so the range must also stabilize; the converse follows by the same dimension-counting argument.

Intuitive explanation

This problem asks you to connect two seemingly opposite properties of powers of a linear operator: when the kernel stops growing and when the range stops shrinking. The key insight is that null⁡Tm\operatorname{null} T^m and range⁡Tm\operatorname{range} T^m are dual notions—one measures what TmT^m "kills," the other what it "reaches"—and they're constrained by the rank-nullity theorem applied repeatedly. If the null space stabilizes at step mm, the rank can't grow further, so the range must also stabilize; the converse follows by the same dimension-counting argument.

Related theory

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