Chemistry

Chemistry

Problem

When mercuric iodide is added to the aqueous solution of potassium iodide then : a. freezing point is raised b. freezing point is lowered c. freezing point does not change d. boiling point does not change
Intuitive explanation

The key here is recognizing a complex ion formation problem where you need to predict what happens when two iodide sources meet. When HgI2\text{HgI}_2 dissolves in excess KI\text{KI}, the iodide ions don't just sit passively—they coordinate around the mercury center, forming a soluble complex. The trick is understanding that while HgI2\text{HgI}_2 is sparingly soluble on its own, the abundance of I−\text{I}^- ions shifts the equilibrium dramatically by creating a stable [HgI4]2−[\text{HgI}_4]^{2-} complex, making the mixture clear instead of the yellow precipitate you'd expect.

Intuitive explanation

The key here is recognizing a complex ion formation problem where you need to predict what happens when two iodide sources meet. When HgI2\text{HgI}_2 dissolves in excess KI\text{KI}, the iodide ions don't just sit passively—they coordinate around the mercury center, forming a soluble complex. The trick is understanding that while HgI2\text{HgI}_2 is sparingly soluble on its own, the abundance of I−\text{I}^- ions shifts the equilibrium dramatically by creating a stable [HgI4]2−[\text{HgI}_4]^{2-} complex, making the mixture clear instead of the yellow precipitate you'd expect.

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