Physics

Physics

Problem

Show that the work done in rotating a single-turn current loop of area AA carrying current II through an angle of 180∘180^{\circ} in a uniform magnetic field of magnitude BB is 2IBA2 I B A.
Intuitive explanation

A current loop in a magnetic field experiences a torque that tries to align its magnetic moment with the field. The key insight is that work equals the change in rotational potential energy: as you rotate the loop against this torque, you're fighting the field's tendency to keep the loop aligned. Since the magnetic potential energy is U=−μBcos⁡θU = -\mu B \cos\theta (where μ=IA\mu = IA is the magnetic moment), rotating 180°180° flips the loop from its lowest energy state to its highest, and the work you must supply equals that total energy change.

Intuitive explanation

A current loop in a magnetic field experiences a torque that tries to align its magnetic moment with the field. The key insight is that work equals the change in rotational potential energy: as you rotate the loop against this torque, you're fighting the field's tendency to keep the loop aligned. Since the magnetic potential energy is U=−μBcos⁡θU = -\mu B \cos\theta (where μ=IA\mu = IA is the magnetic moment), rotating 180°180° flips the loop from its lowest energy state to its highest, and the work you must supply equals that total energy change.

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