Problem

Problem

He2+\text{He}^{2+} ion travels at right angles to a magnetic field of 0.80 T with a velocity of 10510^5 m/s. Find the magnitude of the magnetic force on the ion.
Intuitive explanation

When a charged particle moves perpendicular to a magnetic field, it experiences a force that depends on three things: how much charge it carries, how fast it's moving, and how strong the field is. The key insight is that the magnetic force formula F=qvBsin⁡θF = qvB\sin\theta simplifies beautifully when the motion is perpendicular to the field (θ=90°\theta = 90°), so sin⁡θ=1\sin\theta = 1. Just plug in the charge of the helium ion (which has lost both electrons), the given velocity and field strength, and you're done.

Intuitive explanation

When a charged particle moves perpendicular to a magnetic field, it experiences a force that depends on three things: how much charge it carries, how fast it's moving, and how strong the field is. The key insight is that the magnetic force formula F=qvBsin⁡θF = qvB\sin\theta simplifies beautifully when the motion is perpendicular to the field (θ=90°\theta = 90°), so sin⁡θ=1\sin\theta = 1. Just plug in the charge of the helium ion (which has lost both electrons), the given velocity and field strength, and you're done.

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