Mathematics

Mathematics

Problem

Show that the length of the tangent from any point on the circle x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0 to the circle x2+y2+2gx+2fy+c1=0x^2 + y^2 + 2gx + 2fy + c_1 = 0 is (c1−c)\sqrt{(c_1 - c)} .
Intuitive explanation

The key insight is that the tangent length from a point to a circle depends only on how far that point is from the circle's center, not on where the point sits. Start by rewriting both circles in standard form to identify their centers and radii, then use the tangent-length formula: for a point PP outside a circle with center OO and radius rr, the tangent length is d2−r2\sqrt{d^2 - r^2} where dd is the distance from PP to OO. The elegant part is recognizing that any point on the first circle will be equidistant from the second circle's center, making the tangent length constant across all such points.

Intuitive explanation

The key insight is that the tangent length from a point to a circle depends only on how far that point is from the circle's center, not on where the point sits. Start by rewriting both circles in standard form to identify their centers and radii, then use the tangent-length formula: for a point PP outside a circle with center OO and radius rr, the tangent length is d2−r2\sqrt{d^2 - r^2} where dd is the distance from PP to OO. The elegant part is recognizing that any point on the first circle will be equidistant from the second circle's center, making the tangent length constant across all such points.

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