Physics

This is a rotational kinematics problem—the angular equivalent of finding distance traveled under constant acceleration. Since you know the initial angular velocity (zero), angular acceleration, and time, you can use the rotational version of the kinematic equation $s = ut + \frac{1}{2}at^2$, but with angular quantities: $\theta = \omega_0 t + \frac{1}{2}\alpha t^2$. Just plug in your values and solve.

This is a rotational kinematics problem—the angular equivalent of finding distance traveled under constant acceleration. Since you know the initial angular velocity (zero), angular acceleration, and time, you can use the rotational version of the kinematic equation $s = ut + \frac{1}{2}at^2$, but with angular quantities: $\theta = \omega_0 t + \frac{1}{2}\alpha t^2$. Just plug in your values and solve.