Mathematics

Mathematics

Problem

Let h(x)={x2+2x,x≤13x−1,x>1.h(x)=\begin{cases}x^{2}+2x,& x\le 1\\3x-1,& x>1.\end{cases} Which of the following gives all xx for which hh is increasing? a) (−1,1)(-1,1) b) (−1,∞)(-1,\infty) c) (−∞,−1)(-\infty,-1) d) (1,∞)(1,\infty)
Intuitive explanation

The key is to check where each piece of the function is increasing, then verify continuity at the boundary. For the parabola x2+2xx^2 + 2x on (−∞,1](-\infty, 1], find where its derivative is positive—this tells you which part of that piece slopes upward. For the linear piece 3x−13x - 1 on (1,∞)(1, \infty), the slope is constant. Finally, make sure your answer accounts for the actual domain where each piece applies.

Intuitive explanation

The key is to check where each piece of the function is increasing, then verify continuity at the boundary. For the parabola x2+2xx^2 + 2x on (−∞,1](-\infty, 1], find where its derivative is positive—this tells you which part of that piece slopes upward. For the linear piece 3x−13x - 1 on (1,∞)(1, \infty), the slope is constant. Finally, make sure your answer accounts for the actual domain where each piece applies.

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