Mathematics

Mathematics

Problem

The function g(x)=(k−3)x2+4x−1(k+1)x2−7g(x)=\dfrac{(k-3)x^{2}+4x-1}{(k+1)x^{2}-7} depends on a real parameter kk. (a) Find the value of kk for which lim⁡x→∞g(x)\displaystyle \lim_{x \to \infty} g(x) exists and is equal to 12\dfrac{1}{2}. Show all necessary steps. (b) For the value of kk obtained in part (a), determine lim⁡x→−∞g(x)\displaystyle \lim_{x \to -\infty} g(x). State your answer clearly.
Intuitive explanation

When x→∞x \to \infty for a rational function, the limit depends on the degrees of the numerator and denominator polynomials. If both have the same degree, the limit is the ratio of their leading coefficients—so you need to match those coefficients to get 12\frac{1}{2}. The key insight is that the leading coefficient of the numerator is (k−3)(k-3) and of the denominator is (k+1)(k+1), so set up an equation and solve for kk. Once you have kk, the limit as x→−∞x \to -\infty follows from the same leading-coefficient ratio, since the behavior at −∞-\infty is identical to that at +∞+\infty for rational functions.

Intuitive explanation

When x→∞x \to \infty for a rational function, the limit depends on the degrees of the numerator and denominator polynomials. If both have the same degree, the limit is the ratio of their leading coefficients—so you need to match those coefficients to get 12\frac{1}{2}. The key insight is that the leading coefficient of the numerator is (k−3)(k-3) and of the denominator is (k+1)(k+1), so set up an equation and solve for kk. Once you have kk, the limit as x→−∞x \to -\infty follows from the same leading-coefficient ratio, since the behavior at −∞-\infty is identical to that at +∞+\infty for rational functions.

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