Mathematics

The key is recognizing that intercepts are just special points where the graph crosses the axes. For the y-intercept, you're finding where the curve meets the vertical axis—that's when $x=0$. For the x-intercept, you're finding where it crosses the horizontal axis—that's when $y=0$. Both require simple substitution and solving, but the x-intercept will need you to isolate the exponential term and use logarithms or recognize a power of 2.

The key is recognizing that intercepts are just special points where the graph crosses the axes. For the y-intercept, you're finding where the curve meets the vertical axis—that's when $x=0$. For the x-intercept, you're finding where it crosses the horizontal axis—that's when $y=0$. Both require simple substitution and solving, but the x-intercept will need you to isolate the exponential term and use logarithms or recognize a power of 2.