Mathematics

Mathematics

Problem

Identify the correct defining condition for an odd function ff. a) f(−x)=f(x)f(-x)=f(x) b) f(−x)=−f(x)f(-x)=-f(x) c) f(−x)=∣f(x)∣f(-x)=|f(x)| d) f(−x)=−∣f(x)∣f(-x)=-|f(x)|
Intuitive explanation

An odd function has a special symmetry property: its graph is symmetric about the origin, not just the yy-axis. The key insight is that flipping the input's sign must flip the output's sign too — so if you know f(x)f(x), you can immediately find f(−x)f(-x) by negating it. This algebraic relationship is what makes a function "odd" and distinguishes it from even functions.

Intuitive explanation

An odd function has a special symmetry property: its graph is symmetric about the origin, not just the yy-axis. The key insight is that flipping the input's sign must flip the output's sign too — so if you know f(x)f(x), you can immediately find f(−x)f(-x) by negating it. This algebraic relationship is what makes a function "odd" and distinguishes it from even functions.

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