Physics

Physics

Problem

By what approximate altitude above Earth’s surface must a body be raised so that the acceleration due to gravity decreases by 2%2\%? (Take R=6400 kmR = 6400\,\text{km}.) a) 32 km32\,\text{km} b) 160 km160\,\text{km} c) 130 km130\,\text{km} d) 65 km65\,\text{km}
Intuitive explanation

The key is recognizing that gravitational acceleration depends on distance from Earth's center as g∝1/r2g \propto 1/r^2. When you move to altitude hh, the distance becomes R+hR + h instead of RR, so the new gravity is g′=g0R2/(R+h)2g' = g_0 R^2/(R+h)^2. A 2% decrease means g′=0.98g0g' = 0.98 g_0—set up this ratio and solve for hh using the approximation that h≪Rh \ll R, which lets you expand and simplify dramatically.

Intuitive explanation

The key is recognizing that gravitational acceleration depends on distance from Earth's center as g∝1/r2g \propto 1/r^2. When you move to altitude hh, the distance becomes R+hR + h instead of RR, so the new gravity is g′=g0R2/(R+h)2g' = g_0 R^2/(R+h)^2. A 2% decrease means g′=0.98g0g' = 0.98 g_0—set up this ratio and solve for hh using the approximation that h≪Rh \ll R, which lets you expand and simplify dramatically.

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